Number to words...

Write a program to input a natural number less than 1000 and display it in words. Test your program for the given sample data and some random data.

Input:          29

Output:                  TWENTY NINE

Input:          17

Output:        SEVENTEEN

Input:                    119

Output:                  ONE HUNDRED AND NINETEEN

Input:          220

Output:        TWO HUNDRED AND TWENTY

Solution:-

import java.util.*;

class NumtoWords

{

    public static void main(String args[])

       {

        Scanner sc=new Scanner(System.in);

        String unit[]={"","One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};

        String ten[]={"","Ten","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};

        String ty[]={"","","Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};

        System.out.print("Enter a Number : ");

        int n=sc.nextInt();

        if(n<1 || n>9999)

            System.out.println("Out of Range");

        else

        {

        int th=n/1000; //finding the digit at thousand's place

        int h=(n/100)%10; //finding the digit at hundred's place

        int t=(n/10)%10; //finding the digit at ten's place

        int u=n%10; //finding the digit at unit's place

        System.out.print("Output = ");

        if(th!=0)

        System.out.print(unit[th]+" Thousand");

        if(h!=0)

        System.out.print(" "+unit[h]+" Hundred");

        if((t!=0 || u!=0)&&(th!=0 || h!=0))

        System.out.print(" And");

        if(t==1) //When digit at ten's place is 1, we have different words like Ten, Eleven etc.

        System.out.print(" "+ten[u+1]);

        else //if it is not 1 then we print the words following a normal pattern

        System.out.print(" "+ty[t]+" "+unit[u]);

        }

    }

}